X^2-2x-324=0

Solution for X^2-2x-324=0 equation:

X^2-2X-324=0

a = 1; b = -2; c = -324;
Δ = b2-4ac
Δ = -22-4·1·(-324)
Δ = 1300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1300}=\sqrt{100*13}=\sqrt{100}*\sqrt{13}=10\sqrt{13}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10\sqrt{13}}{2*1}=\frac{2-10\sqrt{13}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10\sqrt{13}}{2*1}=\frac{2+10\sqrt{13}}{2}
$